2014年1月14日星期二

もっともよいOracle 1z1-061試験の問題集

より効果的に試験に合格する方法がわからないなら、私は良いトレーニングサイトを選ぶというアドバイスを差し上げます。そうしたら半分の労力で二倍の効果を得ることができますから。Pass4Testはいつまでも受験生の皆さんにOracleの1z1-061認証試験の真実な試験トレーニング資料を提供することに力を尽くしています。Pass4TestのOracleの1z1-061認証試験の問題集はソフトウェアベンダーがオーソライズした製品で、カバー率が高くて、あなたの大量の時間とエネルギーを節約できます。

Pass4Testの1z1-061問題集は的中率が高いですから、あなたが一回で試験に合格するのを助けることができます。これは多くの受験生たちによって証明されたことです。ですから、問題集の品質を心配しないでください。これは間違いなくあなたが一番信頼できる1z1-061試験に関連する資料です。まだそれを信じていないなら、すぐに自分で体験してください。そうすると、きっと私の言葉を信じるようになります。

試験番号:1z1-061問題集
試験科目:Oracle 「Oracle Database 12c: SQL Fundamentals」
一年間無料で問題集をアップデートするサービスを提供いたします
最近更新時間:2014-01-14
問題と解答:全75問

Pass4Testの助けのもとで君は大量のお金と時間を费やさなくても復楽にOracleの1z1-061認定試験に合格のは大丈夫でしょう。ソフトの問題集はPass4Testが実際問題によって、テストの問題と解答を分析して出来上がりました。Pass4Testが提供したOracleの1z1-061の問題集は真実の試験に緊密な相似性があります。

Pass4TestはOracleの1z1-061認定試験に対して問題集を提供しておるサイトで、現場のOracleの1z1-061試験問題と模擬試験問題集を含みます。ほかのホームページに弊社みたいな問題集を見れば、あとでみ続けて、弊社の商品を盗作することとよくわかります。ass4Testが提供した資料は最も全面的で、しかも更新の最も速いです。

Oracleの1z1-061試験に受かるために一所懸命頑張って勉強していれば、あなたは間違っているのです。もちろん頑張って勉強するのは試験に合格することができますが、望ましい効果を達成できないかもしれません。現在はインターネットの時代で、試験に合格する ショートカットがたくさんあります。Pass4TestのOracleの1z1-061試験トレーニング資料はとても良いトレーニング資料で、あなたが試験に合格することを保証します。この資料は値段が手頃だけでなく、あなたの時間を大量に節約できます。そうしたら、半分の労力で二倍の効果を得ることができます。

購入前にお試し,私たちの試験の質問と回答のいずれかの無料サンプルをダウンロード:http://www.pass4test.jp/1z1-061.html

NO.1 In the customers table, the CUST_CITY column contains the value 'Paris' for the
CUST_FIRST_NAME 'Abigail'.
Evaluate the following query:
What would be the outcome?
A. Abigail PA
B. Abigail Pa
C. Abigail IS
D. An error message
Answer: B

Oracle練習問題   1z1-061   1z1-061   1z1-061

NO.2 Examine the types and examples of relationships that follow:
1.One-to-one a) Teacher to students
2.One-to-many b) Employees to Manager
3.Many-to-one c) Person to SSN
4.Many-to-many d) Customers to products
Which option indicates the correctly matched relationships?
A. 1-a, 2-b, 3-c, and 4-d
B. 1-c, 2-d, 3-a, and 4-b
C. 1-c, 2-a, 3-b, and 4-d
D. 1-d, 2-b, 3-a, and 4-c
Answer: C

Oracle問題集   1z1-061過去問   1z1-061認定試験

NO.3 You need to create a table for a banking application. One of the columns in the table has the
following requirements:
1. You want a column in the table to store the duration of the credit period.
2) The data in the column should be stored in a format such that it can be easily added and
subtracted with date data type without using conversion functions.
3) The maximum period of the credit provision in the application is 30 days.
4) The interest has to be calculated for the number of days an individual has taken a credit for.
Which data type would you use for such a column in the table?
A. DATE
B. NUMBER
C. TIMESTAMP
D. INTERVAL DAY TO SECOND
E. INTERVAL YEAR TO MONTH
Answer: D

Oracle過去問   1z1-061   1z1-061認証試験   1z1-061認定証   1z1-061問題集

NO.4 View the Exhibit for the structure of the student and faculty tables.
You need to display the faculty name followed by the number of students handled by the faculty at
the base location.
Examine the following two SQL statements:
Which statement is true regarding the outcome?
A. Only statement 1 executes successfully and gives the required result.
B. Only statement 2 executes successfully and gives the required result.
C. Both statements 1 and 2 execute successfully and give different results.
D. Both statements 1 and 2 execute successfully and give the same required result.
Answer: D

Oracle   1z1-061認証試験   1z1-061

NO.5 View the Exhibit and examine the structure of the product, component, and PDT_COMP
tables.
In product table, PDTNO is the primary key.
In component table, COMPNO is the primary key.
In PDT_COMP table, <PDTNO, COMPNO) is the primary key, PDTNO is the foreign key referencing
PDTNO in product table and COMPNO is the foreign key referencing the COMPNO in component
table.
You want to generate a report listing the product names and their corresponding component names,
if the component names and product names exist.
Evaluate the following query:
SQL>SELECT pdtno, pdtname, compno, compname
FROM product _____________ pdt_comp
USING (pdtno) ____________ component USING (compno)
WHERE compname IS NOT NULL;
Which combination of joins used in the blanks in the above query gives the correct output?
A. JOIN; JOIN
B. FULL OUTER JOIN; FULL OUTER JOIN
C. RIGHT OUTER JOIN; LEFT OUTER JOIN
D. LEFT OUTER JOIN; RIGHT OUTER JOIN
Answer: C

Oracle   1z1-061   1z1-061認定試験   1z1-061練習問題   1z1-061

NO.6 Examine the structure proposed for the transactions table:
Which two statements are true regarding the creation and storage of data in the above table
structure?
A. The CUST_STATUS column would give an error.
B. The TRANS_VALIDITY column would give an error.
C. The CUST_STATUS column would store exactly one character.
D. The CUST_CREDIT_LIMIT column would not be able to store decimal values.
E. The TRANS_VALIDITY column would have a maximum size of one character.
F. The TRANS_DATE column would be able to store day, month, century, year, hour, minutes,
seconds, and fractions of seconds
Answer: B,C

Oracle問題集   1z1-061練習問題   1z1-061参考書   1z1-061認定資格
Explanation:
VARCHAR2(size)Variable-length character data (A maximum size must be specified:
minimum size is 1; maximum size is 4, 000.)
CHAR [(size)] Fixed-length character data of length size bytes (Default and minimum size
is 1; maximum size is 2, 000.)
NUMBER [(p, s)] Number having precision p and scale s (Precision is the total number of
decimal digits and scale is the number of digits to the right of the decimal point; precision
can range from 1 to 38, and scale can range from -84 to 127.)
DATE Date and time values to the nearest second between January 1, 4712 B.C., and
December 31, 9999 A.D.

NO.7 View the Exhibit and evaluate the structure and data in the CUST_STATUS table.
You issue the following SQL statement:
Which statement is true regarding the execution of the above query?
A. It produces an error because the AMT_SPENT column contains a null value.
B. It displays a bonus of 1000 for all customers whose AMT_SPENT is less than CREDIT_LIMIT.
C. It displays a bonus of 1000 for all customers whose AMT_SPENT equals CREDIT_LIMIT, or
AMT_SPENT is null.
D. It produces an error because the TO_NUMBER function must be used to convert the result of the
NULLIF function before it can be used by the NVL2 function.
Answer: C

Oracle   1z1-061参考書   1z1-061   1z1-061過去問   1z1-061認定証
Explanation:
The NULLIF Function The NULLIF function tests two terms for equality. If they are equal the function
returns a null, else it returns the first of the two terms tested. The NULLIF function takes two
mandatory parameters of any data type. The syntax is NULLIF(ifunequal, comparison_term), where
the parameters ifunequal and comparison_term are compared. If they are identical, then NULL is
returned. If they differ, the ifunequal parameter is returned.

NO.8 Which normal form is a table in if it has no multi-valued attributes and no partial
dependencies?
A. First normal form
B. Second normal form
C. Third normal form
D. Fourth normal form
Answer: B

Oracle認定試験   1z1-061認定試験   1z1-061

NO.9 Evaluate the following SQL statement:
Which statement is true regarding the outcome of the above query?
A. It executes successfully and displays rows in the descending order of PROMO_CATEGORY .
B. It produces an error because positional notation cannot be used in the order by clause with set
operators.
C. It executes successfully but ignores the order by clause because it is not located at the end of the
compound statement.
D. It produces an error because the order by clause should appear only at the end of a compound
query-that is, with the last select statement.
Answer: D

Oracle問題集   1z1-061   1z1-061認定資格   1z1-061   1z1-061

NO.10 Which three tasks can be performed using SQL functions built into Oracle Database?
A. Displaying a date in a nondefault format
B. Finding the number of characters in an expression
C. Substituting a character string in a text expression with a specified string
D. Combining more than two columns or expressions into a single column in the output
Answer: A,B,C

Oracle   1z1-061   1z1-061参考書   1z1-061練習問題

Pass4Testは最新のFCNSA.v5試験問題集と高品質の1Z0-466認定試験の問題と回答を提供します。Pass4TestのHP2-N35 VCEテストエンジンとLOT-409試験ガイドはあなたが一回で試験に合格するのを助けることができます。高品質の00M-654トレーニング教材は、あなたがより迅速かつ簡単に試験に合格することを100%保証します。試験に合格して認証資格を取るのはそのような簡単なことです。

記事のリンク:http://www.pass4test.jp/1z1-061.html

没有评论:

发表评论