2014年2月12日星期三

Pass4Test Microsoftの070-457問題集

Pass4TestのIT専門家たちは受験生の皆さんのニーズを満たすように彼らの豊富な知識と経験を活かして試験トレーニング資料の品質をずっと高めています。受験生の皆さんが一回でMicrosoftの070-457試験に合格することを保証します。Pass4Testの製品を購入したら、あなたはいつでも最新かつ最正確な試験情報を得ることができます。Pass4Testの資料のカバー率が高くて、受験生に便宜を与えられます。それに、問題集の合格率が100パーセントに達するのですから、あなたは安心に試験を受けることができます。

現在でMicrosoftの070-457試験を受かることができます。Pass4TestにMicrosoftの070-457試験のフルバージョンがありますから、最新のMicrosoftの070-457のトレーニング資料をあちこち探す必要がないです。Pass4Testを利用したら、あなたはもう最も良いMicrosoftの070-457のトレーニング資料を見つけたのです。弊社の質問と解答を安心にご利用ください。あなたはきっとMicrosoftの070-457試験に合格できますから。

現在の社会の中で優秀なIT人材が揃て、競争も自ずからとても大きくなって、だから多くの方はITに関する試験に参加してIT業界での地位のために奮闘しています。070-457はMicrosoftの一つ重要な認証試験で多くのIT専門スタッフが認証される重要な試験です。

070-457認定試験の準備をするために、Pass4Test の専門家たちは彼らの豊富な知識と実践を生かして特別なトレーニング資料を研究しました。Pass4Test のMicrosoftの070-457問題集はあなたが楽に試験に受かることを助けます。Pass4Test のMicrosoftの070-457練習テストは070-457試験問題と解答、 070-457 問題集、070-457 書籍や070-457勉強ガイドに含まれています。

試験番号:070-457問題集
試験科目:Microsoft 「Transition Your MCTS on SQL Server 2008 to MCSA: SQL Server 2012, Part 1」
一年間無料で問題集をアップデートするサービスを提供いたします
最近更新時間:2014-02-12
問題と解答:全172問

チャンスは常に準備ができあがった者に属します。しかし、我々に属する成功の機会が来たとき、それをつかむことができましたか。Microsoftの070-457認定試験を受験するために準備をしているあなたは、Pass4Testという成功できるチャンスを掴みましたか。Pass4Testの070-457問題集はあなたが楽に試験に合格する保障です。この問題集は大量な時間を節約させ、効率的に試験に準備させることができます。Pass4Testの練習資料を利用すれば、あなたはこの資料の特別と素晴らしさをはっきり感じることができます。この問題集は間違いなくあなたの成功への近道で、あなたが十分に070-457試験を準備させます。

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NO.1 You are developing a database application by using Microsoft SQL Server 2012. An application that
uses a database begins to run slowly. Your investigation shows the root cause is a query against a
read-only table that has a clustered index.
The query returns the following six columns:
. One column in its WHERE clause contained in a non-clustered index
. Four additional columns
. One COUNT (*) column based on a grouping of the four additional columns
You need to optimize the statement. What should you do?
A. Add a HASH hint to the query.
B. Add a LOOP hint to the query.
C. Add a FORCESEEK hint to the query.
D. Add an INCLUDE clause to the index.
E. Add a FORCESCAN hint to the Attach query.
F. Add a columnstore index to cover the query.
G. Enable the optimize for ad hoc workloads option.
H. Cover the unique clustered index with a columnstore index.
I. Include a SET FORCEPLAN ON statement before you run the query.
J. Include a SET STATISTICS PROFILE ON statement before you run the query.
K. Include a SET STATISTICS SHOWPLAN_XML ON statement before you run the query.
L. Include a SET TRANSACTION ISOLATION LEVEL REPEATABLE READ statement before you run the
query.
M. Include a SET TRANSACTION ISOLATION LEVEL SNAPSHOT statement before you run the query.
N. Include a SET TRANSACTION ISOLATION LEVEL SERIALIZABLE statement before you run the
query.
Answer: F

Microsoft   070-457問題集   070-457   070-457   070-457   070-457

NO.2 You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year
marks for students. The table has marks obtained by 50 students for various subjects. You need to ensure
that the top half of the students arranged by their average marks must be given a rank of 1 and the
remaining students must be given a rank of 2.
Which Transact-SQL query should you use?
A. SELECT StudentCode as Code,
RANK ( ) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks
GROUP BY StudentCode
B. SELECT Id, Name, Marks, DENSE_RANK () OVER (ORDER BY Marks DESC) AS Rank FROM
StudentMarks
C. SELECT StudentCode as Code,
DENSE_RANK () OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks
GROUP BY StudentCode
D. SELECT StudentCode as Code,
NTILE (2) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks
GROUP BY StudentCode
E. SELECT StudentCode AS Code,Marks AS Value
FROM (SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
F. SELECT StudentCode AS Code,Marks AS Value FRCM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER (PARTITION BY SubjectCode ORDER 3Y Marks DESC) AS Rank FRCM StudentMarks)
tmp WHERE Rank = 1
G. SELECT StudentCode AS Code,Marks AS Value FROM
(SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
H. SELECT StudentCode AS Code,Marks AS Value FROM
(SELECT StudentCode, Marks AS Marks,
RANXO OVER (PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
Answer: D

Microsoft練習問題   070-457   070-457認証試験   070-457

NO.3 You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year
marks for students. The table has marks obtained by 50 students for various subjects.
You need to ensure that the following requirements are met:
. Students must be ranked based on their average marks.
. If one or more students have the same average, the same rank must be given to these students.
. Consecutive ranks must be skipped when the same rank is assigned.
Which Transact-SQL query should you use.?
A. SELECT StudentCode as Code, RANK ( ) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM
StudentMarks GROUP BY StudentCode
B. SELECT Id, Name, Marks, DENSE_RANK () OVER (ORDER BY Marks DESC) AS Rank FROM
StudentMarks
C. SELECT StudentCode as Code, DENSE_RANK () OVER (ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks GROUP BY StudentCode
D. SELECT StudentCode as Code, NTILE (2) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM
StudentMarks GROUP BY StudentCode
E. SELECT StudentCode AS Code,Marks AS Value FROM (SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
F. SELECT StudentCode AS Code,Marks AS Value FRCM ( SELECT StudentCode, Marks AS Marks,
RANK() OVER (PARTITION BY SubjectCode ORDER 3Y Marks DESC) AS Rank FRCM StudentMarks)
tmp WHERE Rank = 1
G. SELECT StudentCode AS Code,Marks AS Value FROM (SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
H. SELECT StudentCode AS Code,Marks AS Value FROM (SELECT StudentCode, Marks AS Marks,
RANXO OVER (PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
Answer: A

Microsoft   070-457   070-457練習問題   070-457

NO.4 You are developing a database application by using Microsoft SQL Server 2012. You have a query that
runs slower than expected. You need to capture execution plans that will include detailed information on
missing indexes recommended by the query optimizer.
What should you do?
A. Add a HASH hint to the query.
B. Add a LOOP hint to the query.
C. Add a FORCESEEK hint to the query.
D. Add an INCLUDE clause to the index.
E. Add a FORCESCAN hint to the Attach query.
F. Add a columnstore index to cover the query.
G. Enable the optimize for ad hoc workloads option.
H. Cover the unique clustered index with a columnstore index.
I. Include a SET FORCEPLAN ON statement before you run the query.
J. Include a SET STATISTICS PROFILE ON statement before you run the query.
K. Include a SET STATISTICS SHOWPLAN_XML ON statement before you run the query.
L. Include a SET TRANSACTION ISOLATION LEVEL REPEATABLE READ statement before you run the
query.
M. Include a SET TRANSACTION ISOLATION LEVEL SNAPSHOT statement before you run the query.
N. Include a SET TRANSACTION ISOLATION LEVEL SERIALIZABLE statement before you run the
query.
Answer: K

Microsoft   070-457参考書   070-457認証試験   070-457過去問

NO.5 You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year
marks for students. The table has marks obtained by 50 students for various subjects. You need to ensure
that the following requirements are met:
. Students must be ranked based on their average marks.
. If one or more students have the same average, incremental ranks must be given based on the order
they are created.
. Ranks must be sequential without gaps in between.
Which Transact-SQL query should you use?
A. SELECT StudentCode as Code, RANK ( ) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM
StudentMarks GROUP BY StudentCode
B. SELECT Id, Name, Marks, DENSE_RANK () OVER (ORDER BY Marks DESC) AS Rank FROM
StudentMarks
C. SELECT StudentCode as Code, DENSE_RANK () OVER (ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks GROUP BY StudentCode
D. SELECT StudentCode as Code, NTILE (2) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM
StudentMarks GROUP BY StudentCode
E. SELECT StudentCode AS Code,Marks AS Value FROM (SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
F. SELECT StudentCode AS Code,Marks AS Value FRCM ( SELECT StudentCode, Marks AS Marks,
RANK() OVER (PARTITION BY SubjectCode ORDER 3Y Marks DESC) AS Rank FRCM StudentMarks)
tmp WHERE Rank = 1
G. SELECT StudentCode AS Code,Marks AS Value FROM (SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
H. SELECT StudentCode AS Code,Marks AS Value FROM (SELECT StudentCode, Marks AS Marks,
RANXO OVER (PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
Answer: C

Microsoft   070-457   070-457

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